Bucks G Jrue Holiday voted NBA Teammate of Year

2022-04-26 19:22
Credit: USA Today – Scanpix
Credit USA Today – Scanpix

Milwaukee Bucks guard Jrue Holiday won the NBA's 2021-22 Twyman-Stokes Teammate of the Year Award for the second time on Tuesday.

More than 300 current players cast votes for a group of 12 finalists selected by a panel of league executives.

Holiday received 39 first-place votes and 964 total points to finish ahead of Dallas Mavericks center Boban Marjanovic (48 first-place votes, 936 points) and Chicago Bulls forward DeMar DeRozan (34 and 898).

Free throws this season

77%
17,6
Points made: 17,6
Accuracy: 77,1%
Place in standings: 8
Record max: 33
Record min: 5
Most made FTs: Giannis Antetokounmpo

Holiday, 31, also won the award in 2019-20 while playing for the New Orleans Pelicans. He is the first multiple winner of the award, presented since 2012-13.

He averaged 18.3 points, 6.8 assists, and 4.5 rebounds in 67 games (64 starts) for the defending champion Bucks in 2021-22.

The award is named for Jack Twyman and Maurice Stokes, teammates with the Rochester/Cincinnati Royals from 1955-58.

Stokes was injured on the last day of the 1957-58 season, went into a coma days later, and was ultimately paralyzed. Twyman became his legal guardian and advocate and supported Stokes until his death in 1970. Both men are enshrined in the Basketball Hall of Fame.



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